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Download Oracle Database SQL Exam Dumps

NEW QUESTION 20
Evaluate the following query:

What would be the outcome of the above query?

A. It produces an error because flower braces have been used.B. It executes successfully and introduces an 's at the end of each promo_name in the output.C. It executes successfully and displays the literal " {'s start date was \> " for each row in the output.D. It produces an error because the data types are not matching.

Answer: B

 

NEW QUESTION 21
View the Exhibit and examine PRODUCTS and ORDER_ITEMS tables.

You executed the following query to display PRODUCT_NAME and the number of times the product has been ordered:
SQL>SELECT p.product_name, i.item_cnt
FROM (SELECT product_id, COUNT (*) item_cnt
FROM order_items
GROUP BY product_id) i RIGHT OUTER JOIN products p
ON i.product_id = p.product_id;
What would happen when the above statement is executed?

A. The statement would not execute because the ITEM_CNT alias cannot be displayed in the outer query.B. The statement would not execute because the GROUP BY clause cannot be used in the inline.C. The statement would execute successfully to produce the required output.D. The statement would not execute because inline views and outer joins cannot be used together.

Answer: C

 

NEW QUESTION 22
View the Exhibit and examine the structure of the ORDERS table.

You must select ORDER_ID and ORDER_DATE for all orders that were placed after the last order placed by CUSTOMER_ID 101.
Which query would give you the desired result?

A. SELECT order_id, order_date FROM orders
WHERE order_date >
ANY
(SELECT order_date FROM orders WHERE customer_id = 101);B. SELECT order_id, order_date FROM orders
WHERE order_date > ALL
(SELECT MAX(order_date) FROM orders ) AND customer_id = 101;C. SELECT order_id, order_date FROM orders
WHERE order_date > IN
(SELECT order_date FROM orders WHERE customer_id = 101);D. SELECT order_id, order_date FROM orders
WHERE order_date > ALL
(SELECT order_date FROM orders WHERE customer_id = 101);

Answer: D

Explanation:
Explanation

 

NEW QUESTION 23
Examine the structure of the BOOKS_TRANSACTIONStable:

You want to display the member IDs, due date, and late fee as $2 for all transactions.
Which SQL statement must you execute?

A. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", $2 AS "LATE FEE" FROM BOOKS_TRANSACTIONS;B. SELECT member_id AS "MEMBER ID", due_date AS "DUE DATE", '$2' AS "LATE FEE" FROM BOOKS_TRANSACTIONS;C. SELECT member_id 'MEMBER ID', due_date 'DUE DATE', '$2 AS LATE FEE' FROM BOOKS_TRANSACTIONS;D. SELECT member_id AS MEMBER_ID, due_date AS DUE_DATE, $2 AS LATE_FEE FROM BOOKS_TRANSACTIONS;

Answer: B

 

NEW QUESTION 24
......

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