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NEW QUESTION 21
Which of the following code blocks returns a single-column DataFrame of all entries in Python list throughputRates which contains only float-type values ?
Answer: D
Explanation:
Explanation
spark.createDataFrame(throughputRates, FloatType())
Correct! spark.createDataFrame is the correct operator to use here and the type FloatType() which is passed in for the command's schema argument is correctly instantiated using the parentheses.
Remember that it is essential in PySpark to instantiate types when passing them to SparkSession.createDataFrame. And, in Databricks, spark returns a SparkSession object.
spark.createDataFrame((throughputRates), FloatType)
No. While packing throughputRates in parentheses does not do anything to the execution of this command, not instantiating the FloatType with parentheses as in the previous answer will make this command fail.
spark.createDataFrame(throughputRates, FloatType)
Incorrect. Given that it does not matter whether you pass throughputRates in parentheses or not, see the explanation of the previous answer for further insights.
spark.DataFrame(throughputRates, FloatType)
Wrong. There is no SparkSession.DataFrame() method in Spark.
spark.createDataFrame(throughputRates)
False. Avoiding the schema argument will have PySpark try to infer the schema. However, as you can see in the documentation (linked below), the inference will only work if you pass in an "RDD of either Row, namedtuple, or dict" for data (the first argument to createDataFrame). But since you are passing a Python list, Spark's schema inference will fail.
More info: pyspark.sql.SparkSession.createDataFrame - PySpark 3.1.2 documentation Static notebook | Dynamic notebook: See test 3
NEW QUESTION 22
Which of the following describes characteristics of the Spark driver?
Answer: D
Explanation:
Explanation
The Spark driver requests the transformation of operations into DAG computations from the worker nodes.
No, the Spark driver transforms operations into DAG computations itself.
If set in the Spark configuration, Spark scales the Spark driver horizontally to improve parallel processing performance.
No. There is always a single driver per application, but one or more executors.
The Spark driver processes partitions in an optimized, distributed fashion.
No, this is what executors do.
In a non-interactive Spark application, the Spark driver automatically creates the SparkSession object.
Wrong. In a non-interactive Spark application, you need to create the SparkSession object. In an interactive Spark shell, the Spark driver instantiates the object for you.
NEW QUESTION 23
The code block displayed below contains an error. The code block should produce a DataFrame with color as the only column and three rows with color values of red, blue, and green, respectively.
Find the error.
Code block:
1.spark.createDataFrame([("red",), ("blue",), ("green",)], "color")
Instead of calling spark.createDataFrame, just DataFrame should be called.
Answer: B
Explanation:
Explanation
Correct code block:
spark.createDataFrame([("red",), ("blue",), ("green",)], ["color"])
The createDataFrame syntax is not exactly straightforward, but luckily the documentation (linked below) provides several examples on how to use it. It also shows an example very similar to the code block presented here which should help you answer this question correctly.
More info: pyspark.sql.SparkSession.createDataFrame - PySpark 3.1.2 documentation Static notebook | Dynamic notebook: See test 2
NEW QUESTION 24
The code block shown below should return a column that indicates through boolean variables whether rows in DataFrame transactionsDf have values greater or equal to 20 and smaller or equal to
30 in column storeId and have the value 2 in column productId. Choose the answer that correctly fills the blanks in the code block to accomplish this.
transactionsDf.__1__((__2__.__3__) __4__ (__5__))
2. col("storeId")
3. between(20, 30)
4. &&
5. col("productId")=2B. 1. select
2. "storeId"
3. between(20, 30)
4. &&
5. col("productId")==2C. 1. select
2. col("storeId")
3. between(20, 30)
4. &
5. col("productId")==2D. 1. select
2. col("storeId")
3. between(20, 30)
4. and
5. col("productId")==2E. 1. where
2. col("storeId")
3. geq(20).leq(30)
4. &
5. col("productId")==2
Answer: A
Explanation:
Explanation
Correct code block:
transactionsDf.select((col("storeId").between(20, 30)) & (col("productId")==2)) Although this question may make you think that it asks for a filter or where statement, it does not. It asks explicity to return a column with booleans - this should point you to the select statement.
Another trick here is the rarely used between() method. It exists and resolves to ((storeId >= 20) AND (storeId
<= 30)) in SQL. geq() and leq() do not exist.
Another riddle here is how to chain the two conditions. The only valid answer here is &. Operators like && or and are not valid. Other boolean operators that would be valid in Spark are | and.
Static notebook | Dynamic notebook: See test 1
NEW QUESTION 25
Which of the following code blocks adds a column predErrorSqrt to DataFrame transactionsDf that is the square root of column predError?
Answer: E
Explanation:
Explanation
transactionsDf.withColumn("predErrorSqrt", sqrt(col("predError")))
Correct. The DataFrame.withColumn() operator is used to add a new column to a DataFrame. It takes two arguments: The name of the new column (here: predErrorSqrt) and a Column expression as the new column. In PySpark, a Column expression means referring to a column using the col("predError") command or by other means, for example by transactionsDf.predError, or even just using the column name as a string, "predError".
The question asks for the square root. sqrt() is a function in pyspark.sql.functions and calculates the square root. It takes a value or a Column as an input. Here it is the predError column of DataFrame transactionsDf expressed through col("predError").
transactionsDf.withColumn("predErrorSqrt", sqrt(predError))
Incorrect. In this expression, sqrt(predError) is incorrect syntax. You cannot refer to predError in this way - to Spark it looks as if you are trying to refer to the non-existent Python variable predError.
You could pass transactionsDf.predError, col("predError") (as in the correct solution), or even just "predError" instead.
transactionsDf.select(sqrt(predError))
Wrong. Here, the explanation just above this one about how to refer to predError applies.
transactionsDf.select(sqrt("predError"))
No. While this is correct syntax, it will return a single-column DataFrame only containing a column showing the square root of column predError. However, the question asks for a column to be added to the original DataFrame transactionsDf.
transactionsDf.withColumn("predErrorSqrt", col("predError").sqrt())
No. The issue with this statement is that column col("predError") has no sqrt() method. sqrt() is a member of pyspark.sql.functions, but not of pyspark.sql.Column.
More info: pyspark.sql.DataFrame.withColumn - PySpark 3.1.2 documentation and pyspark.sql.functions.sqrt - PySpark 3.1.2 documentation Static notebook | Dynamic notebook: See test 2
NEW QUESTION 26
......
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