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NEW QUESTION 54
You need to produce a report where each customer's credit limit has been incremented by $1000. In the output, the customer's last name should have the heading Name and the incremented credit limit should be labeled New Credit Limit. The column headings should have only the first letter of each word in uppercase.
Which statement would accomplish this requirement?

A. SELECT cust_last_name AS "Name", cust_credit_limit + 1000AS "New Credit Limit"FROM customers;B. SELECT cust_last_name AS Name, cust_credit_limit + 1000"New Credit Limit"FROM customers;C. SELECT INITCAP (cust_last_name) "Name", cust_credit_limit + 1000INITCAP ("NEW CREDIT LIMIT")FROM customers;D. SELECT cust_last_name AS Name, cust_credit_limit + 1000AS New Credit LimitFROM customers;

Answer: A

 

NEW QUESTION 55
Which three statements are true regarding the SQL WHERE and HAVING clauses? (Choose three.)

A. The HAVING clause conditions can use aliases for the columns.B. The WHERE and HAVING clauses cannot be used together in a SQL statement.C. The WHERE clause is used to exclude rows before grouping data.D. The HAVING clause conditions can have aggregating functions.E. The HAVING clause is used to exclude one or more aggregated results after grouping data.

Answer: C,D,E

 

NEW QUESTION 56
Examine the structure of the EMPLOYEES table.
NameNull?Type
---------------------- ------------
EMPLOYEE_IDNOT NULLNUMBER(6)
FIRST_NAMEVARCHAR2(20)
LAST_NAMENOT NULLVARCHAR2(25)
EMAILNOT NULLVARCHAR2(25)
PHONE NUMBERVARCHAR2(20)
HIRE_DATENOT NULLDATE
JOB_IDNOT NULLVARCHAR2(10)
SALARYNUMBER(8,2)
COMMISSION_PCTNUMBER(2,2)
MANAGER_IDNUMBER(6)
DEPARTMENT_IDNUMBER(4)
There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_ID is 123.
Which query provides the correct output?

A. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.manager_id = m.employee_id)AND e.employee_id = 123;B. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.employee_id = m.manager_id)WHERE e.employee_id = 123;C. SELECT m.last_name, e.manager_idFROM employees e LEFT OUTER JOIN employees mon (e.manager_id = m.manager_id)WHERE e.employee_id = 123;D. SELECT e.last_name, e.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.employee_id = m.employee_id)WHERE e.employee_id = 123;

Answer: B

 

NEW QUESTION 57
Examine the description of the EMPLOYEES table:

The session time zone is the same as the database server
Which two statements will list only the employees who have been working with the company for more than five years?

A. SELECT employee_ name FROM employees WHERE (SYSNAYW - hire_ data / 12> 3 B. SELECT employee_ name FROM employees WHERE (SYSNAYW - hire_ data / 12> 3C. SELECT employee_ name FROM employees WHERE (CUNACV_ DATE - hire_ data / 12> 3D. SELECT employee_ name FROM employees WHERE (SYSTIMESTAMP - hire_ data) / 365>E. SELECT employee_ name FROM employees WHERE (SYSDATE - hire_ data) / 365>5F. SELECT employee_ name FROM employees WHERE (CUARENT_ DATE - hire_ data / 365>5

Answer: E,F

 

NEW QUESTION 58
......


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