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NEW QUESTION 43
Which of the following code blocks stores a part of the data in DataFrame itemsDf on executors?
Answer: D
Explanation:
Explanation
Caching means storing a copy of a partition on an executor, so it can be accessed quicker by subsequent operations, instead of having to be recalculated. cache() is a lazily-evaluated method of the DataFrame. Since count() is an action (while filter() is not), it triggers the caching process.
More info: pyspark.sql.DataFrame.cache - PySpark 3.1.2 documentation, Learning Spark, 2nd Edition, Chapter 7 Static notebook | Dynamic notebook: See test 2
NEW QUESTION 44
Which of the following describes a way for resizing a DataFrame from 16 to 8 partitions in the most efficient way?
Use operation DataFrame.coalesce(0.5) to halve the number of partitions in the DataFrame.
Answer: B
Explanation:
Explanation
Use a narrow transformation to reduce the number of partitions.
Correct! DataFrame.coalesce(n) is a narrow transformation, and in fact the most efficient way to resize the DataFrame of all options listed. One would run DataFrame.coalesce(8) to resize the DataFrame.
Use operation DataFrame.coalesce(8) to fully shuffle the DataFrame and reduce the number of partitions.
Wrong. The coalesce operation avoids a full shuffle, but will shuffle data if needed. This answer is incorrect because it says "fully shuffle" - this is something the coalesce operation will not do. As a general rule, it will reduce the number of partitions with the very least movement of data possible. More info:
distributed computing - Spark - repartition() vs coalesce() - Stack Overflow Use operation DataFrame.coalesce(0.5) to halve the number of partitions in the DataFrame.
Incorrect, since the num_partitions parameter needs to be an integer number defining the exact number of partitions desired after the operation. More info: pyspark.sql.DataFrame.coalesce - PySpark 3.1.2 documentation Use operation DataFrame.repartition(8) to shuffle the DataFrame and reduce the number of partitions.
No. The repartition operation will fully shuffle the DataFrame. This is not the most efficient way of reducing the number of partitions of all listed options.
Use a wide transformation to reduce the number of partitions.
No. While possible via the DataFrame.repartition(n) command, the resulting full shuffle is not the most efficient way of reducing the number of partitions.
NEW QUESTION 45
Which of the following describes the conversion of a computational query into an execution plan in Spark?
Answer: D
Explanation:
Explanation
The executed physical plan depends on a cost optimization from a previous stage.
Correct! Spark considers multiple physical plans on which it performs a cost analysis and selects the final physical plan in accordance with the lowest-cost outcome of that analysis. That final physical plan is then executed by Spark.
Spark uses the catalog to resolve the optimized logical plan.
No. Spark uses the catalog to resolve the unresolved logical plan, but not the optimized logical plan. Once the unresolved logical plan is resolved, it is then optimized using the Catalyst Optimizer.
The optimized logical plan is the input for physical planning.
The catalog assigns specific resources to the physical plan.
No. The catalog stores metadata, such as a list of names of columns, data types, functions, and databases.
Spark consults the catalog for resolving the references in a logical plan at the beginning of the conversion of the query into an execution plan. The result is then an optimized logical plan.
Depending on whether DataFrame API or SQL API are used, the physical plan may differ.
Wrong - the physical plan is independent of which API was used. And this is one of the great strengths of Spark!
The catalog assigns specific resources to the optimized memory plan.
There is no specific "memory plan" on the journey of a Spark computation.
More info: Spark's Logical and Physical plans ... When, Why, How and Beyond. | by Laurent Leturgez | datalex | Medium
NEW QUESTION 46
Which of the following describes Spark's standalone deployment mode?
Answer: C
Explanation:
Explanation
Standalone mode uses only a single executor per worker per application.
This is correct and a limitation of Spark's standalone mode.
Standalone mode is a viable solution for clusters that run multiple frameworks.
Incorrect. A limitation of standalone mode is that Apache Spark must be the only framework running on the cluster. If you would want to run multiple frameworks on the same cluster in parallel, for example Apache Spark and Apache Flink, you would consider the YARN deployment mode.
Standalone mode uses a single JVM to run Spark driver and executor processes.
No, this is what local mode does.
Standalone mode is how Spark runs on YARN and Mesos clusters.
No. YARN and Mesos modes are two deployment modes that are different from standalone mode. These modes allow Spark to run alongside other frameworks on a cluster. When Spark is run in standalone mode, only the Spark framework can run on the cluster.
Standalone mode means that the cluster does not contain the driver.
Incorrect, the cluster does not contain the driver in client mode, but in standalone mode the driver runs on a node in the cluster.
More info: Learning Spark, 2nd Edition, Chapter 1
NEW QUESTION 47
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