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Oracle Database SQL Sample Questions (Q174-Q179):

NEW QUESTION # 174
View the exhibit and examine the description of the DEPARTMENTSand EMPLOYEEStables.

The retrieve data for all the employees for their EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT NAME, the following SQL statement was written:
SELECT employee_id, first_name, department_name
FROM employees
NATURAL JOIN departments;
The desired output is not obtained after executing the above SQL statement. What could be the reason for this?

A. The DEPARTMENTStable is not used before the EMPLOYEEStable in the FROMclause.B. The table prefix is missing for the column names in the SELECTclause.C. The NATURAL JOINclause is missing the USINGclause.D. The EMPLOYEESand DEPARTMENTStables have more than one column with the same column name and data type.

Answer: D

Explanation:
Explanation/Reference:
Explanation:
Natural join needs only one column to be the same in each table. The EMPLOYEESand DEPARTMENTS tables have two columns that are the same (Department_ID and Manager_ID)

NEW QUESTION # 175
View the exhibit and examine the structure of the EMPLOYEEStable.

You want to display all employees and their managers having 100 as the MANAGER_ID. You want the output in two columns: the first column would have the LAST_NAMEof the managers and the second column would have LAST_NAMEof the employees.
Which SQL statement would you execute?
SELECT m.last_name "Manager", e.last_name "Employee"

A. FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE e.manager_id = 100;
SELECT m.last_name "Manager", e.last_name "Employee"B. FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE m.manager_id = 100;
SELECT m.last_name "Manager", e.last_name "Employee"C. FROM employees m JOIN employees e
WHERE m.employee_id = e.manager_id AND e.manager_id = 100D. FROM employees m JOIN employees e
ON e.employee_id = m.manager_id
WHERE m.manager_id = 100;
SELECT m.last_name "Manager", e.last_name "Employee"

Answer: A

NEW QUESTION # 176
Which two statements are true regarding the COUNT function? (Choose two.)

A. COUNT(*) returns the number of rows including duplicate rows and rows containing NULL value in any of the columnsB. The COUNT function can be used only for CHAR, VARCHAR2 and NUMBER data typesC. A SELECT statement using COUNT function with a DISTINCT keyword cannot have a WHERE clauseD. COUNT(cust_id) returns the number of rows including rows with duplicate customer IDs and NULL value in the CUST_ID columnE. COUNT(DISTINCT inv_amt) returns the number of rows excluding rows containing duplicates and NULL values in the INV_AMT column

Answer: A,E

Explanation:
Using the COUNT Function
The COUNT function has three formats:
COUNT(*)
COUNT(expr)
COUNT(DISTINCT expr)
COUNT(*) returns the number of rows in a table that satisfy the criteria of the SELECT
statement, including duplicate rows and rows containing null values in any of the columns.
If a WHERE clause is included in the SELECT statement, COUNT(*) returns the number of
rows that satisfy the condition in the WHERE clause.
In contrast,
COUNT(expr) returns the number of non-null values that are in the column identified by
expr.
COUNT(DISTINCT expr) returns the number of unique, non-null values that are in the
column identified by expr.

NEW QUESTION # 177
View the Exhibit and examine the structure of ORDERS and CUSTOMERS tables. (Choose the best answer.)

You executed this UPDATE statement:

Which statement is true regarding the execution?

A. It would not execute because two tables cannot be referenced in a single UPDATE statement.B. It would not execute because a SELECT statement cannot be used in place of a table name.C. It would not execute because a subquery cannot be used in the WHERE clause of an UPDATE statement.D. It would execute and restrict modifications to the columns specified in the SELECT statement.

Answer: D

NEW QUESTION # 178
Examine the structure and data in the PRICE_LIST table:

You plan to give a discount of 25% on the product price and need to display the discount amount in the same format as the PROD_PRICE.
Which SQL statement would give the required result?

A. SELECT TO_CHAR (TO_NUMBER(prod_price) * .25, '$99,999.00')FROM PRICE_LISTB. SELECT TO_CHAR (TO_NUMBER(prod_price, '$99,999.99') * . 25, '$99,999.00')FROM PRICE_LISTC. SELECT TO_CHAR (prod_price* .25, '$99,999.99')FROM PRICE_LISTD. SELECT TO_NUMBER (TO_NUMBER(prod_price, '$99,999.99') * . 25, '$99,999.00')FROM PRICE_LIST

Answer: B

NEW QUESTION # 179
......

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