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Oracle Database Administration I Sample Questions (Q104-Q109):

NEW QUESTION # 104
Which two statements are true about trace files produced by the Oracle Database server? (Choose two.)

A. They can be written by server processesB. Trace file names are based on the database name concatenated with a sequential numberC. All trace files contain error information that require contacting Oracle SupportD. Trace files are written to the Fast Recovery Area (FRA)E. They can be written by background processes

Answer: A,E

Explanation:
Explanation/Reference: https://gerardnico.com/db/oracle/trace_file


NEW QUESTION # 105
View the Exhibit and examine the structure of the PRODUCTS table.
Which two tasks require subqueries? (Choose two.)

A. Display the number of products whose PROD_LIST_PRICE is more than the average PROD_LIST_PRICEB. Display suppliers whose PROD_LIST_PRICE is less than 1000C. Display the minimum PROD_LIST_PRICE for each product statusD. Display products whose PROD_MIN_PRICE is more than the average PROD_LIST_PRICE of all products, and whose status is orderableE. Display the total number of products supplied by supplier 102 which have a product status of obsolete

Answer: A,D


NEW QUESTION # 106
The stores table has a column START_DATE of data type DATE, containing the date the row was inserted. You only want to display details of rows where START_DATE is within the last 25 months. Which where clause can be used?

A. WHERE MON'THS_BETWEEN (SYSDATE, start_date) <= 25B. WHERE TO_XUMBER(start_date - SYSDATE) <= 25C. WHERE MON'THS_BETWEEN (start_date, SYSDATE) <= 25D. WHERE ADD_MONTHS<start_date, 25) <= SYSDATE

Answer: C


NEW QUESTION # 107
Examine the description of the CUSTOMERS table:

For customers whose income level has a value, you want to display the first name and due amount as 5% of their credit limit. Customers whose due amount is null should not be displayed.
Which query should be used?

A. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT
FROM customers
WHERE cust_income_level != NULL
AND due_amount != NULL;B. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT
FROM customers
WHERE cust_income_level <> NULL
AND due_amount <> NULL;C. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT
FROM customers
WHERE cust_income_level IS NOT NULL
AND due_amount IS NOT NULL;D. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT
FROM customers
WHERE cust_income_level != NULL
AND cust_credit_level !=NULL;E. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT
FROM customers
WHERE cust_income_level IS NOT NULL
AND cust_credit_limit IS NOT NULL;

Answer: E


NEW QUESTION # 108
The CUSTOMERS table has a CUST_CREDIT_LIMIT column of data type NUMBER.
Which two queries execute successfully? (Choose two.)

A. SELECT NVL(TO_CHAR(cust_credit_limit * .15), 'Not Available') FROM customers;B. SELECT NVL2(cust_credit_linit * .15, 'Not Available') FROM customers;C. SELECT TO_CHAR(NVL(cust_credit_limit * .15, 'Not Available')) FROM customers;D. SELECT NVL2(cust_credit_limit, TO_CHAR(cust_credit_limit * .15), 'Not Available') FROM customers;E. SELECT NVL(cust_credit_linit * .15, 'Not Available') FROM customers;

Answer: A,B


NEW QUESTION # 109
......

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