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Oracle Database SQL Sample Questions (Q46-Q51):

NEW QUESTION # 46
View the Exhibit and examine the description of the ORDERS table.

A. WHERE TO_CHAR(order_date,'MON DD YYYY') = 'JAN 20 2003'B. 2003','MON DD YYYY') )
WHERE order_date > TO_CHAR(ADD_MONTHS(SYSDATE,6),'MON DD YYYY')C. Which two WHERE clause conditions demonstrate the correct usage of conversion functions? (Choose two.) WHERE order_date_IN ( TO_DATE('OCT 21 2003','MON DD YYYY'), TO_CHAR('NOV 21D. WHERE order_date > TO_DATE('JUL 10 2006','MON DD YYYY')

Answer: A,D


NEW QUESTION # 47
View the Exhibit and examine the details of PRODUCT_INFORMATIONtable.

You have the requirement to display PRODUCT_NAMEfrom the table where the CATEGORY_IDcolumn has values 12or 13, and the SUPPLIER_IDcolumn has the value 102088. You executed the following SQL statement:
SELECT product_name
FROM product_information
WHERE (category_id = 12 AND category_id = 13) AND supplier_id = 102088; Which statement is true regarding the execution of the query?

A. It would not execute because the same column has been used in both sides of the ANDlogical operator to form the condition.B. It would not execute because the entire WHEREclause condition is not enclosed within the parentheses.C. It would execute but the output would return no rows.D. It would execute and the output would display the desired result.

Answer: C

Explanation:
Explanation/Reference:


NEW QUESTION # 48
Examine the structure of the BOOKS_ TRANSACTIONS table:
Examine the SQL statement:
Which statement is true about the outcome?

A. It displays details for only members A101and A102 who have borrowed before today with RM as TRANSACTION_TYPE.B. It displays details for members who have borrowed before today with RM as TRANSACTION_TYPE and the details for members A101 or A102.C. It displays details only for members who have borrowed before today with RM as TRANSACTION_TYPE.D. It displays details for members who have borrowed before today's date with either RM as TRANSACTION_TYPE or MEMBER_ID as A101 and A102.

Answer: C


NEW QUESTION # 49
The CUSTOMERS table has a CUST_CREDIT_LIMIT column of data type NUMBER.
Which two queries execute successfully?

A. SELECT TO_CHAR(NVL(cust_credit_limit * .15, 'Not Available')) FROM customers;B. SELECT NVL2 (cust_credit_limit * .15, 'Not Available') FROM customers;C. SELECT NVL2(cust_credit_limit, TO_CHAR(cust_credit_limit * .15), 'Not Available') FROM customers;D. SELECT NVL(TO_CHAR(cust_credit_limit * .15), 'Not Available') FROM customers;E. SELECT NVL (cust_credit_limit * .15, 'Not Available') FROM customers;

Answer: B,D


NEW QUESTION # 50
View the exhibit and examine the structure of the PROMOTIONS table.

You have to generate a report that displays the promo name and start date for all promos that started after the last promo in the 'INTERNET' category.
Which query would give you the required output?

A. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date > ALL (SELECT promo_begin_dateFROM promotionsWHERE promo_category = 'INTERNET');B. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date IN (SELECT promo_begin_dateFROM promotionsWHERE promo_category= 'INTERNET');C. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date> ALL (SELECT MAX (promo_begin_date)FROM promotions) ANDpromo_category= 'INTERNET';D. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date> ANY (SELECT promo_begin_dateFROM promotionsWHERE promo_category= 'INTERNET');

Answer: A


NEW QUESTION # 51
......

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