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NEW QUESTION 37
Which of the following statements about the differences between actions and transformations is correct?

A. Actions are evaluated lazily, while transformations are not evaluated lazily.B. Actions can be queued for delayed execution, while transformations can only be processed immediately.C. Actions generate RDDs, while transformations do not.D. Actions can trigger Adaptive Query Execution, while transformation cannot.E. Actions do not send results to the driver, while transformations do.

Answer: D

Explanation:
Explanation
Actions can trigger Adaptive Query Execution, while transformation cannot.
Correct. Adaptive Query Execution optimizes queries at runtime. Since transformations are evaluated lazily, Spark does not have any runtime information to optimize the query until an action is called. If Adaptive Query Execution is enabled, Spark will then try to optimize the query based on the feedback it gathers while it is evaluating the query.
Actions can be queued for delayed execution, while transformations can only be processed immediately.
No, there is no such concept as "delayed execution" in Spark. Actions cannot be evaluated lazily, meaning that they are executed immediately.
Actions are evaluated lazily, while transformations are not evaluated lazily.
Incorrect, it is the other way around: Transformations are evaluated lazily and actions trigger their evaluation.
Actions generate RDDs, while transformations do not.
No. Transformations change the data and, since RDDs are immutable, generate new RDDs along the way.
Actions produce outputs in Python and data types (integers, lists, text files,...) based on the RDDs, but they do not generate them.
Here is a great tip on how to differentiate actions from transformations: If an operation returns a DataFrame, Dataset, or an RDD, it is a transformation. Otherwise, it is an action.
Actions do not send results to the driver, while transformations do.
No. Actions send results to the driver. Think about running DataFrame.count(). The result of this command will return a number to the driver. Transformations, however, do not send results back to the driver. They produce RDDs that remain on the worker nodes.
More info: What is the difference between a transformation and an action in Apache Spark? | Bartosz Mikulski, How to Speed up SQL Queries with Adaptive Query Execution

 

NEW QUESTION 38
The code block shown below should show information about the data type that column storeId of DataFrame transactionsDf contains. Choose the answer that correctly fills the blanks in the code block to accomplish this.
Code block:
transactionsDf.__1__(__2__).__3__

A. 1. limit
2. "storeId"
3. printSchema()B. 1. limit
2. 1
3. columnsC. 1. select
2. storeId
3. dtypesD. 1. select
2. "storeId"
3. printSchema()E. 1. select
2. "storeId"
3. print_schema()

Answer: B

Explanation:
Explanation
Correct code block:
transactionsDf.select("storeId").printSchema()
The difficulty of this question is that it is hard to solve with the stepwise first-to-last-gap approach that has worked well for similar questions, since the answer options are so different from one another. Instead, you might want to eliminate answers by looking for patterns of frequently wrong answers.
A first pattern that you may recognize by now is that column names are not expressed in quotes. For this reason, the answer that includes storeId should be eliminated.
By now, you may have understood that the DataFrame.limit() is useful for returning a specified amount of rows. It has nothing to do with specific columns. For this reason, the answer that resolves to limit("storeId") can be eliminated.
Given that we are interested in information about the data type, you should question whether the answer that resolves to limit(1).columns provides you with this information. While DataFrame.columns is a valid call, it will only report back column names, but not column types. So, you can eliminate this option.
The two remaining options either use the printSchema() or print_schema() command. You may remember that DataFrame.printSchema() is the only valid command of the two. The select("storeId") part just returns the storeId column of transactionsDf - this works here, since we are only interested in that column's type anyways.
More info: pyspark.sql.DataFrame.printSchema - PySpark 3.1.2 documentation Static notebook | Dynamic notebook: See test 3

 

NEW QUESTION 39
The code block displayed below contains an error. The code block should return all rows of DataFrame transactionsDf, but including only columns storeId and predError. Find the error.
Code block:
spark.collect(transactionsDf.select("storeId", "predError"))

A. Instead of collect, collectAsRows needs to be called.B. The take method should be used instead of the collect method.C. Columns storeId and predError need to be represented as a Python list, so they need to be wrapped in brackets ([]).D. Instead of select, DataFrame transactionsDf needs to be filtered using the filter operator.E. The collect method is not a method of the SparkSession object.

Answer: E

Explanation:
Explanation
Correct code block:
transactionsDf.select("storeId", "predError").collect()
collect() is a method of the DataFrame object.
More info: pyspark.sql.DataFrame.collect - PySpark 3.1.2 documentation
Static notebook | Dynamic notebook: See test 2

 

NEW QUESTION 40
Which of the following describes properties of a shuffle?

A. Shuffles belong to a class known as "full transformations".B. Operations involving shuffles are never evaluated lazily.C. A shuffle is one of many actions in Spark.D. Shuffles involve only single partitions.E. In a shuffle, Spark writes data to disk.

Answer: E

Explanation:
Explanation
In a shuffle, Spark writes data to disk.
Correct! Spark's architecture dictates that intermediate results during a shuffle are written to disk.
A shuffle is one of many actions in Spark.
Incorrect. A shuffle is a transformation, but not an action.
Shuffles involve only single partitions.
No, shuffles involve multiple partitions. During a shuffle, Spark generates output partitions from multiple input partitions.
Operations involving shuffles are never evaluated lazily.
Wrong. A shuffle is a costly operation and Spark will evaluate it as lazily as other transformations. This is, until a subsequent action triggers its evaluation.
Shuffles belong to a class known as "full transformations".
Not quite. Shuffles belong to a class known as "wide transformations". "Full transformation" is not a relevant term in Spark.
More info: Spark - The Definitive Guide, Chapter 2 and Spark: disk I/O on stage boundaries explanation - Stack Overflow

 

NEW QUESTION 41
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