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NEW QUESTION 53
Examine the structure of the BOOKS_ TRANSACTIONS table:

Examine the SQL statement:

Which statement is true about the outcome?

A. It displays details for members who have borrowed before today's date with either RM as TRANSACTION_TYPE or MEMBER_ID as A101 and A102.B. It displays details for only members A101and A102 who have borrowed before today with RM as TRANSACTION_TYPE.C. It displays details only for members who have borrowed before today with RM as TRANSACTION_TYPE.D. It displays details for members who have borrowed before today with RM as TRANSACTION_TYPE and the details for members A101 or A102.

Answer: C

 

NEW QUESTION 54
View the Exhibit and examine the structure of the ORDERS table.

You must select ORDER_ID and ORDER_DATE for all orders that were placed after the last order placed by CUSTOMER_ID 101.
Which query would give you the desired result?

A. SELECT order_id, order_date FROM orders
WHERE order_date > ALL
(SELECT MAX(order_date) FROM orders ) AND customer_id = 101;B. SELECT order_id, order_date FROM orders
WHERE order_date > IN
(SELECT order_date FROM orders WHERE customer_id = 101);C. SELECT order_id, order_date FROM orders
WHERE order_date >
ANY
(SELECT order_date FROM orders WHERE customer_id = 101);D. SELECT order_id, order_date FROM orders
WHERE order_date > ALL
(SELECT order_date FROM orders WHERE customer_id = 101);

Answer: D

Explanation:
Explanation

 

NEW QUESTION 55
Examine the commands used to create DEPARTMENT_DETAILS and COURSE_DETAILS tables:

You want to generate a list of all department IDs that do not exist in the COURSE_DETAILS table.
You execute the SQL statement:

What is the outcome?

A. It fails because the ON clause condition is not valid.B. It executes successfully but displays an incorrect list.C. It executes successfully and displays the required list.D. It fails because the join type used is incorrect.

Answer: C

 

NEW QUESTION 56
BOOK_SEQ is an existing sequence in your schema.
Which two CREATE TABLE commands are valid?

A. CREATE TABLE bookings (
bk_id NUMBER(4) NOT NULL PRIMARY KEY,
start_date DATE NOT NULL,
end_date DATE DEFAULT SYSDATE);B. CREATE TABLE bookings ( bk_id NUMBER(4),
start_date DATE DEFAULT SYSDATE,
end_date DATE DEFAULT (end_date >= start_date));C. CREATE TABLE bookings (
bk_id NUMBER(4) DEFAULT book_seq.CURRVAL,
start_date DATE DEFAULT SYSDATE,
end_date DATE DEFAULT start date);D. CREATE TABLE bookings (
bk_id NUMBER(4) DEFAULT book_seq.NEXTVAL PRIMARY KEY,
start_date DATE DEFAULT SYSDATE,
end_date DATE DEFAULT SYSDATE NOT NULL);E. CREATE TABLE bookings (
bk_id NUMBER(4) NOT NULL DEFAULT book_seq.CURRVAL,
start_date DATE NOT NULL,
end_date DATE DEFAULT SYSDATE);

Answer: A,D

 

NEW QUESTION 57
......

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